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54m^2-294=0
a = 54; b = 0; c = -294;
Δ = b2-4ac
Δ = 02-4·54·(-294)
Δ = 63504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{63504}=252$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-252}{2*54}=\frac{-252}{108} =-2+1/3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+252}{2*54}=\frac{252}{108} =2+1/3 $
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